Shakia Hainesworth
Tuesday, August 9, 2011
Improper integrals...converges or diverges?
If the integrand is dx/(xsqrt(x^2 - 1)), the integral converges (compare with dx/x^2). If the integrand is sqrt(x^2 - 1)dx/x, the integral diverges (it bebaves like Integral(dx)).
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